Final answer:
The average value of function j(x) on the interval from x = 0 to x = 3 is found by integrating j(x) over the interval and dividing by the interval's length, assuming a uniform distribution, the average would be the midpoint of the interval.
Step-by-step explanation:
To find the average value of the function j(x) over the interval from x = 0 to x = 3, we would typically integrate the function over this interval and then divide by the length of the interval. However, the specific function j(x) is not given here. If we assume that j(x) represents a uniform distribution or a constant function over the interval, the average value can be easily computed. For instance, if j(x) is constant, then the average value would simply be that constant value.
In the case of a uniform distribution, the average value of j(x) over the interval would just be the midpoint of the interval since the values are equally distributed. Since we do not have the specific function, we cannot provide a numeric answer. However, the general formula to find the average value of such a function over an interval [a, b] is given by:
\[\frac{1}{b - a}\int_{a}^{b} j(x) \, dx\]
If the function j(x) is uniform in the interval given, then the average value is simply:
\[\frac{(a + b)}{2}\]