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Write the equation of the sphere in standard form. 2x2 + 2y2 + 2z2 = 4x − 24z + 1 Find its center and radius.

User Kostrykin
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1 Answer

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Final answer:

The equation of the sphere is (x - h)^2 + (y - k)^2 + (z - l)^2 = r^2. We can put the given equation in standard form by completing the square for the x and z terms. The center of the sphere is (2, 0, 6) and the radius is sqrt(-167 - 24z).

Step-by-step explanation:

The equation of the sphere is given by:

(x - h)2 + (y - k)2 + (z - l)2 = r2

In this case, we have the equation 2x2 + 2y2 + 2z2 = 4x - 24z + 1. To put it in standard form, we need to complete the square for the x and z terms. Let's start by completing the square for the x terms:

(x - 2)2 + 2y2 + 2z2 = 4 - 4 - 24z + 1

(x - 2)2 + 2y2 + 2z2 = -23 - 24z

Next, let's complete the square for the z terms:

(x - 2)2 + 2y2 + (z - 6)2 = -23 - 24(6) - 24z

(x - 2)2 + 2y2 + (z - 6)2 = -167 - 24z

Now we can see that the center of the sphere is (2, 0, 6) and the radius is sqrt(-167 - 24z).

User Liu Kang
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