The x and the y intercept of the function are (-2.5, 0) and (0, 1)
How to determine the x and the y intercept of the function
From the question, we have the following parameters that can be used in our computation:
x - (y + 2) = 3(x - 2y + 1)
We set x to 0 to calculate the y-intercept
So, we have
0 - (y + 2) = 3(0 - 2y + 1)
Evaluate
-y - 2 = -6y + 3
This gives
6y - y = 2 + 3
Evaluate
y = 1
We set y to 0 to calculate the x-intercept
x - (0 + 2) = 3(x - 2(0) + 1)
So, we have
x - 2 = 3x + 3
Evaluate
2x =- 5
So, we have
x = -2.5
Hence, the x and the y intercept of the function are (-2.5, 0) and (0, 1)