Final answer:
To calculate the average force during an automobile crash test, the formula F = m \( \Delta v\) / \( \Delta t\) is used, yielding a force of 28,000 N.
Step-by-step explanation:
The subject question inquires about the average force exerted on a wall by a car during an automobile crash test. To calculate this force, we use Newton's second law of motion and the formula for average force, which is F = m \( \Delta v\) / \( \Delta t\), where F is the force, m is the mass of the car, \( \Delta v\) is the change in velocity, and \( \Delta t\) is the time over which the change occurs. Given a 2000kg car going at 14m/s, brought to a stop in 0.5s:
\( F = 2000kg \times (0m/s - 14m/s) / 0.5s \)
\( F = -28,000 kg \cdot m/s^2 \)
The average force of the car on the wall is 28,000 N in the direction opposite to the initial motion of the car, indicated by a negative sign, which is common when indicating opposing forces. So, the correct answer to the question is C. 28,000 N.