The change in energy for the reaction Li(g) + Cl(g) → Li+(g) + Cl-(g) is 171 kJ/mol.
There is the calculation of ΔE for the reaction Li(g) + Cl(g) → Li+(g) + Cl-(g) using the data in the table:
ΔE = ΔH = -IE - EA
Where:
ΔE is the change in energy
ΔH is the enthalpy change
IE is the ionization energy
EA is the electron affinity
For lithium:
IE = 520 kJ/mol
For chlorine:
EA = -349 kJ/mol
Now, we can plug these values into the equation:
ΔE = -520 kJ/mol - (-349 kJ/mol) = 171 kJ/mol
Therefore, the change in energy for the reaction Li(g) + Cl(g) → Li+(g) + Cl-(g) is 171 kJ/mol.