Final answer:
The energy being released by this light source is approximately 3.313 x 10^-19 J.
Step-by-step explanation:
To calculate the energy of a photon, we can use the formula E = hf, where E is the energy, h is Planck's constant (6.626 × 10^-34 J·s), and f is the frequency of the photon.
Substituting the given frequency (5.0 x 10^14 Hz) into the formula, we get:
E = (6.626 × 10^-34 J·s) (5.0 x 10^14 Hz) = 3.313 x 10^-19 J
Therefore, the energy being released by this light source is approximately 3.313 x 10^-19 J, which is option A.