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A 5000 kg airplane makes a horizontal turn in a radius of 0.62 mi with a velocity of 112.5 mi/h. How much centripetal force (in N) is required?

a) 12.5 kN
b) 15.6 kN
c) 18.8 kN
d) 27.2 kN

User SebScoFr
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1 Answer

3 votes

Final answer:

To calculate the centripetal force required for the airplane, use the formula F = (m * v^2) / r. Substituting the given values, the centripetal force is approximately 256,745 N.

Step-by-step explanation:

To calculate the centripetal force required, we can use the formula:

F = (m * v^2) / r

Where F is the centripetal force, m is the mass of the airplane, v is the velocity, and r is the radius of the turn.

Substituting the given values, we have:

F = (5000 kg * (112.5 mi/h)^2) / 0.62 mi

Converting the velocity and radius to metric units, we get:
F = (5000 kg * (50.5376 m/s)^2) / (996.88 m)

Calculating the expression, we find that the centripetal force required is approximately 256,745 N.

Therefore, none of the given options (a, b, c, d) are correct. The correct answer is not listed.

User Tremby
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