Solving
2x - 6y = -12 ----------- equ1
x + 2y = 14 ................ equ 2 mutilplied by 2 = 2 x + 4 y = 28 ------equ 3
We want to use elimination method,
Equation 3 - Equation 1 ,
2x - 6y = -12 ----------- equ1
2 x + 4 y = 28 -------------equ 3
4 y - ( -6 y ) = 28 - ( - 12 )
4y + 6y = 28 + 12
10 y = 40
Divide both sides by 10
y = 40 / 10
y = 4
put y = 4 in equ 1 , we have ;
2x - 6y = -12 --- equ 1
2x - 6 (4) = - 12
2 x - 24 = -12
2x = -12 + 24
2x = 12
Divide both sides by 2, we have :
x = 6
CONCLUSION : x = 6 , y = 4