Final answer:
The speed of the car while it was moving along the floor is approximately 7.04 m/s.
Step-by-step explanation:
The question asks about the speed of a toy car while it was moving along the floor. To solve this, we can use the concept of conservation of mechanical energy. Since the car reaches a maximum vertical height of 2.67 m above the floor, we can find the potential energy at that height and equate it to the initial kinetic energy of the car.
Using the equation for potential energy (PE = mgh) and considering the mass (m) of 211 g and the height (h) of 2.67 m, we can calculate the potential energy to be 5.76 J. Then, using the equation for kinetic energy (KE = 1/2 mv^2), where m is the mass (0.211 kg) and v is the speed of the car on the floor, we can solve for v.
Setting the potential energy equal to the initial kinetic energy:
PE = KE
mgh = 1/2 mv^2
0.211 kg * 9.8 m/s^2 * 2.67 m = 1/2 * 0.211 kg * v^2
Simplifying the equation:
5.2134 J = 0.1051 v^2
Dividing both sides by 0.1051:
49.601 m^2/s^2 = v^2
Taking the square root of both sides:
v = 7.04 m/s
Therefore, the speed of the car while it was moving along the floor is approximately 7.04 m/s.