Question

In ABC, we are told that b = 5, B = 19°, and 4C = 66º. Solve for a and c. Round to the nearest tenth.

Answer 1

Okay, here we have this:

Considering that we know two angles and the measure of one side we are going to use the law of sine and cosine to find the measure of the other two sides:

`\begin{gathered} (b)/(\sin(B))=(c)/(\sin(C)) \\ (5)/(\sin(19))=(c)/(\sin (66)) \\ c=(5\sin\left(66^(\circ\:)\right))/(\sin\left(19^(\circ\:)\right)) \\ c\approx14.0 \end{gathered}`

Angle A=180°-19°-66°

Angle A=95°