Question

What mass of your hydrate would be required to create 1.00 cup of water? Use dimensional analysis to solve this problem.

BaCl2 is your hydrate
0.96g BaCl2
0.17g H20
0.0046 moles BaCl2
0.0094 moles H20
2 moles H20/1 mole BaCl2

Answer 1

To create 1.00 cup of water, approximately 0.166 grams of BaCl2 hydrate would be required.

Step-by-step explanation:

To solve this problem using dimensional analysis, we first need to determine the conversion factor between the mass of BaCl2 and the mass of water. According to the given information, the molar ratio between BaCl2 and H2O is 2 mol H2O / 1 mol BaCl2. We can use this ratio to convert the mass of BaCl2 to moles of H2O.

Given that the mass of BaCl2 is 0.96 g and the molar mass of BaCl2 is 208.23 g/mol, we can calculate the number of moles of BaCl2:

(0.96 g BaCl2) x (1 mol BaCl2 / 208.23 g BaCl2) = 0.0046 mol BaCl2

Now we can use the molar ratio to convert moles of BaCl2 to moles of H2O:

(0.0046 mol BaCl2) x (2 mol H2O / 1 mol BaCl2) = 0.0092 mol H2O

Since we want to determine the mass of the hydrate that would be required to create 1.00 cup of water, we need to convert moles of H2O to grams. The molar mass of H2O is 18.015 g/mol, so:

(0.0092 mol H2O) x (18.015 g H2O / 1 mol H2O) ≈ 0.166 g H2O