Final answer:
To find the acceleration of an object dropped from a cliff, one can use the kinematic equation v^2 = u^2 + 2as. However, when the known values are applied to this equation, the result does not match the available multiple-choice answers, hinting at an issue with the provided numbers or the underlying assumptions.
Step-by-step explanation:
The question pertains to the physics concept of acceleration due to gravity, specifically using one of the kinematic equations to solve for acceleration when an object is dropped from a cliff. To find the acceleration, we can use the kinematic equation v^2 = u^2 + 2as, where
- v is the final velocity (12 m/s)
- u is the initial velocity (0 m/s, since it starts from rest)
- a is the acceleration
- s is the distance traveled (22 m)
Plugging in the given values and solving for a, we get:
12^2 = 0 + 2*a*22
144 = 44a
a = 144 / 44 = 3.27 m/s²
However, this value doesn't match with any of the provided options A to D. The correct value near to earth's surface should be around 9.8 m/s² signifying a potential error in the given values or calculations.