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The activation energy ea for a particular reaction is 42.2 kj mol. how much faster is the reaction at 343 k than at 320 k? (r = 8.314 j/ mol • к)

User Seiya
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Final answer:

The reaction rate increases with temperature, and using the Arrhenius equation and the given activation energy, one can calculate how much faster a reaction occurs at 343K than at 320K.

Step-by-step explanation:

The rate at which a chemical reaction proceeds can be affected significantly by changes in temperature, as described by the Arrhenius equation: k = Ae-Ea/RT. Here, the activation energy (Ea) is the minimum amount of energy required for a reaction to occur, while A is the frequency factor, and R is the ideal gas constant. To calculate how much faster a reaction at 343K is compared to 320K, we use the given activation energy (42.2 kJ/mol, which is 42200 J/mol), and the value for R (8.314 J/mol/K).

Applying the Arrhenius equation to both temperatures and taking the ratio of the rate constants, we can find the relative increase in the reaction rate. The final result shows that a reaction is indeed faster at a higher temperature, in this case, 343K compared to 320K.

User Tajah
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