Final answer:
The genotypic and phenotypic proportions in the children would be 1/4 ABMN, 1/4 ABN, 1/4 AMN, 1/4 AN. The probability of the first born child being AB and MN would be 1/4.
Step-by-step explanation:
In a mating between a male with blood type AB and blood type MN and a female with blood type O and N, the possible genotypic and phenotypic proportions in their children would be:
- Genotypic: 1/4 ABMN, 1/4 ABN, 1/4 AMN, 1/4 AN
- Phenotypic: 1/4 type AB with both antigens, 1/4 type A with antigen M, 1/4 type A with antigen N, 1/4 type A with neither antigen
Assuming the first born child is a male, the probability that he will have blood type AB and MN would be 1/4.