Question

Score on last try: 0 of 1 pts. see details for more. next question get a similar question you can retry this question below 93 students at a college were asked whether they had completed their required english 101 course, and 48 students said "yes". construct the 80% confidence interval for the proportion of students at the college who have completed their required english 101 course. enter your answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places. 0.691 incorrect < p < 0.844 incorrect

Answer 1

To construct the 80% confidence interval for the proportion of students who have completed their required English 101 course, we can use the plus-four method. The confidence interval is 0.466 < p' < 0.566.

Step-by-step explanation:

To construct a confidence interval for the proportion of students who have completed their required English 101 course, we can use the plus-four method. The formula for the confidence interval is:

p' - EBP < p' + EBP

where p' is the sample proportion and EBP is the margin of error. In this case, the sample proportion is 48/93 = 0.516 and the margin of error is calculated using the plus-four method, which is (48+2)/(93+4) - 0.516 = 0.566 - 0.516 = 0.05.

Substituting these values into the formula, we get:

0.516 - 0.05 < p' < 0.516 + 0.05

Rounding to three decimal places, the confidence interval is 0.466 < p' < 0.566. Therefore, we can be 80% confident that the proportion of students at the college who have completed their required English 101 course is between 0.466 and 0.566.