Question

Write the equation of the line that passes through the points (-1, 10) and (5, 2)

Answer 1

`y=-(4)/(3)x +(26)/(3)`

Explanation:

1) if the point A has coordinates (-1;10) and the point B - (5;2), then it is possible to write common view of the required equation of the line:

`(x-X_A)/(X_B-X_A) =(y-Y_A)/(Y_B-Y_A);`

2) if to substitute the coordinates of A&B into the common equation, then:

`(x+1)/(5+1) =(y-10)/(2-10); \ => (x+1)/(6)=(y-10)/(-8);`

3) finally, in slope-intersection form:

3y= -4x+26; ⇔ y= -4/3 x +26/3.

P.S. the suggested way of the solution is not the only one.