Question

A spring has a force constant of 60000 n/m. how far must it be stretched for its potential energy to be 44 j?

Answer 1

The spring must be stretched by approximately 8.1 cm for its potential energy to be 44 J.

Step-by-step explanation:

To calculate how far the spring must be stretched, we can use the equation:

PE = 1/2 kx^2

where PE is the potential energy, k is the force constant of the spring, and x is the displacement.

Rearranging the equation, we have:

x =√(2PE/k)

Plugging in the given values, we get:

x =√(2 * 44 J / 60000 N/m) = 0.081 m = 8.1 cm

Therefore, the spring must be stretched by approximately 8.1 cm for its potential energy to be 44 J.