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A spinner has 10 equally sized sections, 2 of which are blue and 8 of which are red. the spinner is spun and, at the same time, a fair coin is tossed. what is the probability that the spinner lands on blue and the coin toss is tails? do not round your answer.

User Obabs
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Final answer:

The probability of the spinner landing on blue and the coin toss resulting in tails is ⅖, which is calculated by multiplying the probability of the spinner landing on blue (⅓) and the probability of getting tails on the coin toss (⅒).

Step-by-step explanation:

The probability that the spinner lands on blue and the coin toss results in tails can be calculated by multiplying the probability of each individual event. The probability of the spinner landing on blue (P(blue)) is ⅓ because there are 2 blue sections out of 10. The probability of tossing a tails (P(tails)) with a fair coin is ⅒ because there are 2 possible outcomes, heads or tails, and they are equally likely.

The combined probability of both events happening (P(blue and tails)) is the product of the individual probabilities:

  • P(blue) = ⅓
  • P(tails) = ⅒
  • P(blue and tails) = P(blue) × P(tails) = ⅓ × ⅒ = ⅖

Therefore, the probability that the spinner lands on blue and the coin toss is tails is ⅖ or 0.10.

User Nasir T
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