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A slide on a playground rises at a 45° angle. The top of the slide is 20 feet above the ground. How far does a child travel down the slide? Round answer to the nearest hundredth place.

A slide on a playground rises at a 45° angle. The top of the slide is 20 feet above-example-1
User Siv
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1 Answer

5 votes
5 votes

x=Let's illustrate the problem first. Assuming the height of the slide is right-angled to the ground.

To determine the length of the slide, we can use sine function.


\sin \theta=\frac{opposite\text{ side}}{\text{hypotenuse}}

In the illustration, the opposite side of the angle 45° is 20ft whereas the hypotenuse is the length of the slide. Let's plug in these values to the function above. Assume x = length of the slide.


\sin 45=(20ft)/(x)

Solve for x.


\begin{gathered} x=(20ft)/(\sin 45) \\ x=20\sqrt[]{2}ft \\ x\approx28.28ft \end{gathered}

The length of the slide and the distance the child has to travel down the slide is approximately 28.28 ft. (Option C)

A slide on a playground rises at a 45° angle. The top of the slide is 20 feet above-example-1
User Saeid Nourian
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