Question

An ideal gas has a pressure 1.86 atm, temperature 412 k, and volume 6.85 l. when 0.126 moles of additional gas are injected into the container at constant temperature and volume, what is the new pressure?

Answer 1

The new pressure of the ideal gas after injecting additional moles at constant temperature and volume is calculated using the ideal gas law. The initial moles are first determined with the given conditions, then the additional moles are added, and the final pressure is found by reapplying the ideal gas law with the updated number of moles.

Upon solving the new pressure of the ideal gas is 1.86 atm.

Step-by-step explanation:

To find the new pressure, we can use the combined gas law equation: PV/T = PV/T

Let's denote the initial pressure, volume, and temperature as P₁, V₁, and T₁ respectively. And the final pressure is P₂. Since the temperature and volume are constant, we can write the equation as:

P₁V₁/T₁ = P₂V₂/T₁

Substituting the given values:

P₁ = 1.86 atm

V₁ = 6.85 L

T₁ = 412 K

V₂ = V₁ + 0.126 moles

Plugging in the values, the equation becomes:

1.86 * 6.85 / 412 = P2 * (6.85 + 0.126) / 412

Simplifying the equation gives us:

P₂ = 1.86 * 6.85 / (6.85 + 0.126)

P₂ = 1.86 atm