Question

A 15.75-g piece of iron absorbs 1,086.75 joules of heat energy and its temperature changes from 25.0°C to 175.0°C. Calculate the specific heat capacity of iron.

Answer 1

0.46 J/g°C

Step-by-step explanation

Given:

Mass of iron, m = 15.75 g

Quantity of heat, q = 1086.75 J

Initial temperature, T₁ = 25.0 °C

Final temperature, T₂ = 1750 °C

What to find:

The specific heat capacity, c of the iron.

Step-by-step solution:

The specific heat capacity of the iron can be calculated using the formula below:

`q=mc(T_2-T_1)`

Put the values of the given parameters into the formula:

`\begin{gathered} 1086.75=15.75* c*(175.0-25.0) \\ \\ 1086.75=15.75* c*150 \\ \\ 1086.75=2362.5c \\ \\ Divide\text{ }both\text{ }sides\text{ }by\text{ }2362.5 \\ \\ (1086.75)/(1362.5)=(2362.5c)/(2362.5) \\ \\ c=0.46\text{ }J\text{/}g^0C \end{gathered}`

The specific heat capacity, c of the iron = 0.46 J/g°C