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A 6.57 kg ball rolls across the street at a rate of 7 m/s. What is the KE of the ball before it hits the curb?

User Lilezek
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1 Answer

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Final answer:

The kinetic energy of a 6.57 kg ball rolling at 7 m/s is approximately 161 joules (J) before it hits the curb, calculated using the formula KE = 1/2mv².

Step-by-step explanation:

To calculate the kinetic energy (KE) of a ball with a mass of 6.57 kg rolling at a speed of 7 m/s before it hits the curb, we can use the formula KE = 1/2mv² where m is the mass and v is the velocity of the object. Plugging in the values:

KE = 1/2 × 6.57 kg × (7 m/s)²

KE = 1/2 × 6.57 kg × 49 m²/s²

KE = 1/2 × 6.57 kg × 49 J

KE = 3.285 kg × 49 J

KE = 160.965 J

Therefore, the kinetic energy of the ball is approximately 161 J.

User OnkarDhane
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