Question

14. The population of a town increased from 2,692 in 2008 to 5,712 in 2010. Find the absolute and percent increase. Give the percent increase to at least one decimal place.Absolute increase: peoplePercent increase: %

Answer 1

Hello

The population at 2008 = 2692

The population at 2010 = 5712

The absolute increase is simply the difference between the two population over the two time periods

Absolute increase is

`5712-2692=3020`

The absolute difference is 3020

The percentage increase would be the ratio between the change in population to the original population multiplied by 100

`(5712-2692)/(2692)*100=(3020)/(2692)*100=112.18\text{ \%}`

The percentage increase is approximately equals to 112.2%

From the calculation above, the absolute difference is 3020 and the percentage increase is 112.2%