Question

Starting at 11th Street, Dylan rides his bike due North on Corral Hollow Rd with the wind at his back. He rides at 6.6 m/s. He then stops for a 5 min break, turns around, and rides back to 11th Street; because of the headwind, his speed is only 4.40 m/s. The whole trip takes 19.5 min. What was his displacement from 11th Street when he stopped for a break?

a. 0 m
b. 165 m
c. 330 m
d. 495 m

Answer 1

Dylan's displacement from 11th Street when he stopped for a break is 1073.2 m.

Step-by-step explanation:

To find Dylan's displacement from 11th Street when he stopped for a break, we need to calculate the distances he traveled in both directions.

First, let's calculate the distance he traveled with the wind at his back. Since he rode at a speed of 6.6 m/s for the duration of 19.5 min (0.325 hours), the distance can be found using the formula distance = speed × time. Therefore, the distance he traveled with the wind at his back is 6.6 m/s × 0.325 hours = 2.14 km.

Next, let's calculate the distance he traveled against the headwind. Since he rode at a speed of 4.4 m/s for the duration of 14.5 min (0.242 hours), the distance can be found using the same formula. Therefore, the distance he traveled against the headwind is 4.4 m/s × 0.242 hours = 1.0668 km.

To find his displacement, we subtract the distance traveled against the headwind from the distance traveled with the wind at his back. Therefore, his displacement from 11th Street when he stopped for a break is 2.14 km - 1.0668 km = 1.0732 km or 1073.2 m.