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3x-2y + z = 0 6x + 2x +3z=-2 3x- 4y+ 5z = 5solve by row echelon form​

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Final answer:

The system of equations is transformed to a triangular matrix using row operations to simplify to row echelon form for easier solution finding.

Step-by-step explanation:

To solve the system of equations 3x - 2y + z = 0, 6x + 2x +3z = -2, and 3x - 4y + 5z = 5 using row echelon form, we will perform row operations to simplify the system to a triangular matrix, where all elements below the main diagonal are zeros. Here are the steps:

  • Write the system in matrix form.
    [3 -2 1 | 0]
    [8 0 3 | -2]
    [3 -4 5 | 5]
  • Use row operations to get zeros below the main diagonal.
    [3 -2 1 | 0] R1
    [0 16 1 | -2] R2 - 8/3 * R1
    [0 -2 4 | 5] R3 - R1
  • Continue with row operations until the matrix is in row echelon form.
    [3 -2 1 | 0] R1
    [0 16 1 | -2] R2
    [0 0 3 | 5.5] R3 + R2/8
  • Solve the triangular system starting from the last row.

After obtaining the triangular matrix, we can solve for z from the last equation, substitute back to find y from the second equation, and finally, substitute y and z to find x from the first equation.

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