Question

How many moles of CO are needed to react with an excess of Fe2O3 to produce 209.7 g Fe?Fe2O3(s) + 3CO(g) —> 3CO2(g) +2Fe(s)

Answer 1

Step 1

The reaction provided must be written as follows:

Fe2O3 (s) + 3 CO (g) => 3 CO2 (g) + 2 Fe (s) (completed and balanced)

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Step 2

Information provided:

The limiting reactant CO and the excess reactant Fe2O3

209.7 g needs to be produced

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Information needed:

The molar mass of Fe = 55.85 g/mol

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Step 3

By stoichiometry

Procedure:

Fe2O3 (s) + 3 CO (g) => 3 CO2 (g) + 2 Fe (s)

3 moles CO ----------- 2 x 55.85 g Fe

X ----------- 209.7 g Fe

X = 209.7 g Fe x 3 moles CO/ 2 x 55.85 g Fe

X = 5.632 moles

Answer: 5.632 moles of CO are needed