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Unpolarized light with an intensity of 72 W/m^2 passes through two polarizing filters. If the light that emerges from the second filter has an intensity of 9 W/m^2, what is the angle between the two filters?

a. 30°
b. 45°
c. 60°
d. 90°

1 Answer

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Final answer:

The angle between the two polarizing filters that results in an unpolarized light intensity reduction from 72 W/m^2 to 9 W/m^2 is 60 degrees.

Step-by-step explanation:

The question pertains to the intensity reduction of unpolarized light as it passes through two polarizing filters at a certain angle. When light passes through the first polarizer, its intensity becomes half of the original intensity. The intensity of light after passing through a second polarizer is given by Malus's Law, which states that the intensity I after the second polarizer is I = I0cos2(θ), where I0 is the intensity of the light after the first polarizer, and θ is the angle between the axes of the two polarizers.

Given that the initial intensity is 72 W/m2 (after the first polarizer), and the final intensity is 9 W/m2, we use the relation 9 = (72/2)cos2(θ) to find the angle.

After solving the equation, we find cos2(θ) = 0.25 which implies that cos(θ) = 0.5. Thus, the angle θ is 60°, which is option c.

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