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What volume of 0.0441M sulfuric acid is required to titrate 25cm³ of carbonate? (Round off to 2 decimal places).

A) 0.02 cm³
B) 1.10 cm³
C) 56.65 cm³
D) 0.05 cm³

1 Answer

5 votes

Final answer:

Without the concentration of the carbonate solution and the complete balanced chemical equation, it isn't possible to determine the exact volume of 0.0441M sulfuric acid needed to titrate 25 cm³ of a carbonate solution.

Step-by-step explanation:

To determine the volume of 0.0441M sulfuric acid required to titrate 25 cm³ of a carbonate solution, we need to know the concentration of the carbonate solution and the chemical reaction involved. Since these details are not provided, we can't give a precise answer.

However, titrations generally involve the concept of molarity and volume, and the reaction typically for a carbonate would be CO₃²⁻ + H₂SO₄ → H₂O + CO₂ + SO₄²⁻. To solve such a problem, you would use the stoichiometry of the reaction and the molarity of the acid to find the volume of acid needed to neutralize the carbonate.

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