Final answer:
The induced emf in the short-shunt compound generator is approximately 208.4 V. The armature current is approximately 0.058 A.
Step-by-step explanation:
The induced emf in a short-shunt compound generator can be calculated using the equation:
E = V - Ia(Ra + Rs)
where E is the induced emf, V is the load voltage (220 V), Ia is the armature current, Ra is the armature resistance (0.05 Ω), and Rs is the series-field resistance (0.30 Ω).
The armature current can be calculated using Ohm's Law:
Ia = (V - Eb) / (Ra + Rs)
where Eb is the back emf.
Considering the 1.0 V per brush for contact drop, the induced emf can be calculated as:
E = 220 V - 30 A * (0.05 Ω + 0.30 Ω) - 2 V
E = 220 V - 9.6 Ω - 2 V
E ≈ 208.4 V
The armature current can be calculated as:
Ia = (220 V - 208.4 V) / (0.05 Ω + 0.30 Ω + 200 Ω)
Ia ≈ 11.6 V / 200.35 Ω
Ia ≈ 0.058 A