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Consider two signals:

x₁=5sin(π416t) + sin(π1144t) + 10sin(π1560t)
x₂=20sin(π784t) + 5sin(π1568t) + 30sin(π2156t)

Find the period of x¹ and x².

User Elvio
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Final answer:

The period of x₁ is 416/π seconds and the period of x₂ is 784/π seconds.

Step-by-step explanation:

The period of a wave is the time it takes for one complete cycle to occur. To find the period of a wave, we need to determine the time it takes for the wave to complete one cycle. For the given signals, the period of x₁ can be found by identifying the smallest repeating pattern in the signal. In this case, the smallest repeating pattern is sin(π/416t), which completes one cycle every time t = 416/π seconds. Therefore, the period of x₁ is 416/π seconds. Similarly, the smallest repeating pattern in x₂ is sin(π/784t), which completes one cycle every time t = 784/π seconds. Therefore, the period of x₂ is 784/π seconds.

User Grapefrukt
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