Final answer:
To find the magnetic field inside a solenoid, we use the equation B = μnI, where B is the magnetic field, μ is the permeability of free space, n is the number of turns per unit length, and I is the current flowing through the solenoid. In this case, the solenoid has a length of 50 cm, 100 turns, and carries a current of 2.5A. Plugging in the values, we find that the magnetic field inside the solenoid is 4×10-5 T.
Step-by-step explanation:
In order to find the magnetic field (B) inside a solenoid, we can use the equation B = μnI, where B is the magnetic field, μ is the permeability of free space, n is the number of turns per unit length, and I is the current flowing through the solenoid.
In this case, the solenoid has a length of 50 cm, 100 turns, and carries a current of 2.5A. To find the magnetic field inside the solenoid, we need to know the number of turns per unit length. We can find this using the formula n = N/L, where N is the total number of turns and L is the length of the solenoid.
Plugging in the values, n = 100/0.5 = 200 turns per meter. Now, we can calculate the magnetic field using B = μnI. Given that μ is a constant value, B = (4π×10-7 T·m/A)(200 turns/m)(2.5 A) = 4×10-5 T.