Question

A. How can ETAP be use for reliability assessment of power distribution system?

b. What are the Advantages and disadvantages of ETAP over the simulation method in Reliability of distribution power system?

Answer 1

To transmit 100 MW of power at 200 kV, a current of 500 A is needed. The power dissipated by transmission lines with a resistance of 1.00 Ω is 250 kW, which is 0.25% of the total power transmitted.

Step-by-step explanation:

To answer the question regarding the transmission of power, we use the formula Power (P) = Voltage (V) * Current (I). To find the current required to transmit 100 MW (1.00×10² MW) of power at 200 kV

• Current (I) = Power (P) / Voltage (V)
• Current (I) = 1.00×10² MW / 200 kV
• Current (I) = 500 A

For the second part, the power dissipated by the transmission lines with a resistance of 1.00 Ω can be found using the formula Power Dissipated (Pd) = Current^2 (I²) * Resistance (R):

• Power Dissipated (Pd) = (500 A)² * 1.00 Ω
• Power Dissipated (Pd) = 250,000 W or 250 kW

Finally, to calculate the percentage of power lost in the transmission lines:

• Percentage Loss = (Power Dissipated / Power Transmitted) * 100
• Percentage Loss = (250 kW / 100,000 kW) * 100
• Percentage Loss = 0.25%