Question

What is the resistance of a lightbulb that uses an average power of 75.0 W when connected to a 60.0-Hz power source having a maximum voltage of 172 V?

Answer 1

The resistance of the lightbulb is approximately 394.453 Ω.

Step-by-step explanation:

To find the resistance of a lightbulb, we can use the formula:

R = (V^2) / P

where R is the resistance, V is the voltage, and P is the power. In this case, the voltage is the maximum voltage of 172 V and the power is 75.0 W. Plugging in these values, we get:

R = (172^2) / 75.0 = 394.453 Ω

Therefore, the resistance of the lightbulb is approximately 394.453 Ω.