Final answer:
The given S and P values are used to calculate the reactive power (Q). For capacitive loads, Q is negative, resulting in a complex power of (1.6 - 1.2) kVA.
Step-by-step explanation:
The student is looking to calculate the complex power in an AC circuit. Given the apparent power (S) is 2 KVA and the real power (P) is 1.6 KW (Capacitive), we can calculate the reactive power (Q) using the formula:
S2 = P2 + Q2
First, we find the absolute value of Q:
|Q| = √(S2 - P2)
|Q| = √((22) - (1.62)) KVA
|Q| = √(4 - 2.56) KVA
|Q| = √(1.44) KVA
|Q| = 1.2 KVA
Because the power is capacitive, the reactive power Q is negative, so we have:
Q = -1.2 KVA
Therefore, the complex power is (1.6 - 1.2) kVA, or 1.6 + j(-1.2) kVA in complex form.