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A generator with an internal resistance of 40ohms is used to insert a step wave with an amplitude of 40 V into a transmission line with a characteristic impedance of 75ohms. If the steady state voltage observed in the line at long times is 32 V what is the load connected to the receiving end of the line?

User Netwons
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Final answer:

The question pertains to finding the load resistance at the end of a transmission line, given a generator with a known internal resistance, characteristic impedance of the line, and steady state voltage. The load resistance can be calculated using voltage division, taking into account the generator voltage, internal resistance, and characteristic impedance.

Step-by-step explanation:

The student is asking about the behavior of electrical circuits in the context of power transmission and impedance matching in electrical engineering. The question involves a generator, transmission line, and load impedance. It also involves understanding steady-state voltage and transmission line theory, specifically the use of characteristic impedance and internal resistance of a generator to determine the load connected at the receiving end of the transmission line.

In the scenario given, the generator has an internal resistance (Rg) of 40 ohms and the transmission line has a characteristic impedance (Z0) of 75 ohms. When a voltage step of 40 V is applied, the steady-state voltage observed at the line is 32 V. To determine the load resistance (Rl) connected at the receiving end, we can use the voltage division rule and the concept that, at steady state, the voltage across the load is the same as the voltage on the line. The relationship between the voltages and resistances can be described by:

Vl = Vg * (Rl / (Rl + Rg + Z0))

Where Vl is the load voltage, and Vg is the generator voltage. Plugging in the known values (Vl = 32 V and Vg = 40 V) and solving for Rl gives us the value of the load resistance connected to the transmission line.

User FAQi
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