Final answer:
The correct relationship between the distances s1 and s2 covered by a particle under constant acceleration over two consecutive 5 second intervals when starting from rest is s2 = 3s1.
Step-by-step explanation:
The student is asking about the relationship between distances covered by a particle under constant acceleration over two equal intervals of time.
When a particle starts from rest and moves with constant acceleration, the distance it covers is proportional to the square of the time elapsed. The distance s1 is covered in the first 5 seconds, while s2 is covered in the next 5 seconds. Using the equations of motion, we can derive the relationship between s1 and s2.
For the first interval, s1 = 1/2 * a * t1^2, where a is the acceleration and t1 is 5 s.
For the second interval, t2 will be 10 s because it is the total time elapsed.
The total distance covered in 10 s is s1 + s2, which can be written as, s1 + s2 = 1/2 * a * t2^2.
Substituting t2 = 10 s and solving for s2 in terms of s1, we find that s2 = 3s1.
The correct relation between s1 and s2 is therefore s2 = 3s1.