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What is the potential energy of a 2 kg potted plant that is on a 1 m high plant stand? (Ep = mgh)

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Final answer:

The potential energy of the 2 kg potted plant on a 1 m high stand is calculated using the equation Ep = mgh. Substituting the known values into this equation gives us a potential energy of 19.6 Joules.

Step-by-step explanation:

To calculate the potential energy of the 2 kg potted plant on a 1 m high plant stand, we use the equation Ep = mgh. Here, m equals the mass of the potted plant, g is the gravitational acceleration, and h is the height the plant is raised above the ground.

For the given plant, we have:


  • m (mass) = 2 kg

  • g (gravitational acceleration) = 9.8 m/s²

  • h (height) = 1 m

Plugging these values into the formula:

Ep = (2 kg) * (9.8 m/s²) * (1 m) = 19.6 J

Therefore, the gravitational potential energy of the potted plant is 19.6 Joules.

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