181k views
5 votes
What is the potential energy of a 2 kg potted plant that is on a 1 m high plant stand? (Ep = mgh)

1 Answer

7 votes

Final answer:

The potential energy of the 2 kg potted plant on a 1 m high stand is calculated using the equation Ep = mgh. Substituting the known values into this equation gives us a potential energy of 19.6 Joules.

Step-by-step explanation:

To calculate the potential energy of the 2 kg potted plant on a 1 m high plant stand, we use the equation Ep = mgh. Here, m equals the mass of the potted plant, g is the gravitational acceleration, and h is the height the plant is raised above the ground.

For the given plant, we have:


  • m (mass) = 2 kg

  • g (gravitational acceleration) = 9.8 m/s²

  • h (height) = 1 m

Plugging these values into the formula:

Ep = (2 kg) * (9.8 m/s²) * (1 m) = 19.6 J

Therefore, the gravitational potential energy of the potted plant is 19.6 Joules.

User Ykaragol
by
8.2k points

Related questions

asked Nov 23, 2024 234k views
ChiakiYu asked Nov 23, 2024
by ChiakiYu
8.7k points
1 answer
1 vote
234k views
1 answer
0 votes
89.2k views
1 answer
0 votes
135k views