140k views
1 vote
The four-byte hexadecimal sequence 8D AB 52 AB stored in consecutive memory cells in a little-endian architecture represents ___________ (decimal) when interpreted as a 32-bit unsigned integer.

a) 2,217,330,315
b) 2,217,324,651
c) 2,221,989,860
d) 2,221,989,675

1 Answer

6 votes

Final answer:

The correct decimal value for the hexadecimal sequence 8D AB 52 AB, when interpreted as a 32-bit unsigned integer in little-endian architecture, is 2,217,330,315.

Step-by-step explanation:

The four-byte hexadecimal sequence 8D AB 52 AB stored in consecutive memory cells in a little-endian architecture represents a certain number when interpreted as a 32-bit unsigned integer. To determine the correct decimal value, we need to rearrange the bytes in the order they would be read, due to the little-endian storage. In little-endian, the bytes are ordered from the least significant byte to the most significant byte, so the sequence AB 52 AB 8D has to be read in the reverse order to how it might be written in big-endian format.

To convert this to a decimal number, we can concatenate the bytes in their proper order and convert from hexadecimal to decimal. Therefore, the sequence AB 52 AB 8D in hexadecimal represents the decimal value 2,217,330,315.

The correct answer is a) 2,217,330,315.

User Janoliver
by
9.0k points