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Calculate the [OH⁻] of an aqueous solution with a H3₀+ = 6.67 x 10⁻⁷

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Final answer:

To calculate the [OH-] of the aqueous solution, we can use the equation Kw = [H3O+][OH-] and rearrange the equation to solve for [OH-]. Substituting the given value of [H3O+], we find that [OH-] is 1.5 x 10-8 M.

Step-by-step explanation:

The given information states that the [H3O+] of an aqueous solution is 6.67 x 10-7 M. However, we need to calculate the concentration of [OH-] in the solution.

To do this, we can use the equation Kw = [H3O+][OH-] = 1.0 x 10-14 M2. Since we know the value of [H3O+], we can rearrange the equation and solve for [OH-].

Substituting the given value, we have:

[OH-] = Kw / [H3O+] = (1.0 x 10-14 M2) / (6.67 x 10-7 M) = 1.5 x 10-8 M.

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