47.6k views
2 votes
Suppose you are constructing a wooden rectangular frame.

If the length is half a foot shorter than 2 times the width and the perimeter of the frame is 35 feet, then find the length and width of the frame?

User AGuegu
by
8.6k points

1 Answer

6 votes

Final answer:

To solve the problem, we set up equations based on the given relationships and calculated the width to be 6 feet and the length to be 11.5 feet for the wooden rectangular frame.

Step-by-step explanation:

Given that the length is half a foot shorter than twice the width and the perimeter is 35 feet, we can start by setting up equations to represent these relationships. Let w be the width and l be the length in feet of the wooden frame. Using the information provided:

  • Length (l) = 2w - 0.5
  • Perimeter (P) = 2l + 2w = 35 feet

First, we substitute the expression for the length into the perimeter equation:

  • 35 = 2(2w - 0.5) + 2w
  • 35 = 4w - 1 + 2w
  • 35 = 6w - 1
  • 35 + 1 = 6w
  • 36 = 6w
  • w = 6 feet

Now, we find the length by substituting the width back into the length's equation:

  • l = 2(6) - 0.5
  • l = 12 - 0.5
  • l = 11.5 feet

The width is 6 feet and the length is 11.5 feet.

User Uchechi
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories