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Suppose you are constructing a wooden rectangular frame.

If the length is half a foot shorter than 2 times the width and the perimeter of the frame is 35 feet, then find the length and width of the frame?

User AGuegu
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1 Answer

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Final answer:

To solve the problem, we set up equations based on the given relationships and calculated the width to be 6 feet and the length to be 11.5 feet for the wooden rectangular frame.

Step-by-step explanation:

Given that the length is half a foot shorter than twice the width and the perimeter is 35 feet, we can start by setting up equations to represent these relationships. Let w be the width and l be the length in feet of the wooden frame. Using the information provided:

  • Length (l) = 2w - 0.5
  • Perimeter (P) = 2l + 2w = 35 feet

First, we substitute the expression for the length into the perimeter equation:

  • 35 = 2(2w - 0.5) + 2w
  • 35 = 4w - 1 + 2w
  • 35 = 6w - 1
  • 35 + 1 = 6w
  • 36 = 6w
  • w = 6 feet

Now, we find the length by substituting the width back into the length's equation:

  • l = 2(6) - 0.5
  • l = 12 - 0.5
  • l = 11.5 feet

The width is 6 feet and the length is 11.5 feet.

User Uchechi
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