Question

Write an equation for the reaction of cuprous chloride with 1-phenylpropyne​.

Answer 1

Equation for the reaction of cuprous chloride with 1-phenylpropyne​ is
`\[ \text{2 CuCl} + \text{2 C}_(9)\text{H}_(8) \rightarrow \text{2 Cu} + \text{2 C}_(9)\text{H}_(6) + \text{2 HCl} \]`

Step-by-step explanation:

The reaction between cuprous chloride (CuCl) and 1-phenylpropyne (C₉H₈) involves the displacement of the chloride ion (Cl⁻) by the alkyne, leading to the formation of copper(I) acetylide and hydrogen chloride. The balanced chemical equation represents this transformation, where two moles of cuprous chloride react with two moles of 1-phenylpropyne, yielding two moles each of copper metal (Cu), 1-phenylpropyne (C₉H₆), and hydrogen chloride (HCl).

Cuprous chloride is known for its ability to act as a source of copper(I) ions, which can coordinate with alkynes to form metal acetylides. In this case, the phenyl group in 1-phenylpropyne undergoes nucleophilic attack on the copper ion, resulting in the formation of copper(I) phenylacetylide. The liberation of hydrogen chloride is indicative of the displacement of the chloride ion during this reaction.