Final answer:
The student's question relates to calculating the mean and rms values of the output voltage for a single-phase half-wave uncontrolled rectifier with an RL load, using a supply voltage of Vs(t) = 100 sin(wt). There is an inconsistency with the conduction angle provided, assuming a typical half-wave rectifier the angles would not exceed 180°. Calculations would need to consider the actual conducting portion of the waveform to determine the exact output voltage values.
Step-by-step explanation:
The subject of the question is a single-phase half-wave uncontrolled rectifier with an RL (resistor and inductor) load. To find the mean and rms values of the output voltage, we need to consider the supply voltage given by Vs(t) = 100 sin(wt). However, it is important to note that the conduction angle is specified as 220°, which means that the diode will only conduct for a portion of the input AC cycle.
Unfortunately, due to the provided conduction angle which is greater than 180°, there appears to be a misunderstanding as for a half-wave rectifier, the conduction angle should not exceed 180°. If we proceed with the conventional assumption of a 180° conduction angle for normal half-wave rectification, we would only analyze the positive half-cycles of the sine wave.
The average (mean) value of the output voltage will be less than the peak value of the supply voltage due to the time during which the diode is not conducting. The rms value takes into account the effective value of the voltage over the complete cycle, considering the square root of the average of the voltage squared over the period of the waveform.
However, to accurately compute both the mean and the rms value of the output voltage, the actual conduction angle (if deviating from 180°) and waveform would have to be incorporated into the calculation.