186k views
0 votes
What is the value of g(h(-4)) when using the given functions g(n) = 4n + 5 and h(n) = n^2 - n?

A) -4
B) 15
C) 16
D) -15

User GNassro
by
7.8k points

1 Answer

4 votes

Final answer:

To find the value of g(h(-4)), substitute -4 into h(n) and then substitute the result into g(n). The value of g(h(-4)) is 85.

Step-by-step explanation:

To find the value of g(h(-4)), we need to substitute the value of -4 into the function h(n) = n^2 - n and then substitute the result into the function g(n) = 4n + 5.

First, substitute -4 into the function h(n) = n^2 - n:

h(-4) = (-4)^2 - (-4) = 16 + 4 = 20

Next, substitute the result 20 into the function g(n) = 4n + 5:

g(20) = 4(20) + 5 = 80 + 5 = 85

Therefore, the value of g(h(-4)) is 85.

User Anirban Bhui
by
6.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories