Question

Write the first ten terms of a sequence whose first term is -10 and whose common difference is -2.

a. -10, -12, -14, -16, -18, -20, -22, -24, -26, -28
b. -10, -8, -6, -4, -2, 0, 2, 4, 6, 8
c. -10, -8, -12, -14, -16, -18, -20, -22, -24, -26
d. -10, -7, -5, -3, -1, 1, 3, 5, 7, 9

Answer 1

The first ten terms of a sequence starting with -10 and with a common difference of -2 are: -10, -12, -14, -16, -18, -20, -22, -24, -26, -28.

Step-by-step explanation:

The question asks us to write the first ten terms of a sequence with a first term of -10 and a common difference of -2. To find the terms of the sequence, we start with the first term and add the common difference to each subsequent term.

• 1st term: -10 (the given first term)
• 2nd term: -10 + (-2) = -12
• 3rd term: -12 + (-2) = -14
• 4th term: -14 + (-2) = -16
• 5th term: -16 + (-2) = -18
• 6th term: -18 + (-2) = -20
• 7th term: -20 + (-2) = -22
• 8th term: -22 + (-2) = -24
• 9th term: -24 + (-2) = -26
• 10th term: -26 + (-2) = -28

Therefore, the first ten terms of the sequence are: -10, -12, -14, -16, -18, -20, -22, -24, -26, -28.