Question

2A professional pyro technician shoots fireworks vertically into the air from the ground with an initial velocity of 192

feet per second. The height in feet of the fireworks is given by h(t) = -16t² + 192t.
a. How long does it take for the fireworks to reach the maximum height?
b. What is the maximum height reached by the firework?

Answer 1

See below

Explanation:

Maximum height will be found at the t value = - b/2a

b = 192 a = -16

so max height will be at t = - 192/(2 * -16) = 6 s

Max height will be h = -16(6^2) + 192(6) = 576 ft