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RQPO is a trapezoid. What is the value of x?

2

63°

(6x + 9°

R

User Subhacom
by
5.1k points

1 Answer

4 votes

Answer:

18°

Explanation:

Find the diagram attached

From the diagram, since the opposite side are parallel, the sum of the adjacent angle is 180 degrees

From the diagram, m<RQP + m<QPO = 180

Given

m<RQP = 6x+9

m<QPO = 63

Substitute

6x+9+63 = 180

6x + 72 = 180

6x = 180 - 72

6x = 108

x = 108/6

x = 18 degrees

Hence the value of x is 18°

RQPO is a trapezoid. What is the value of x? 2 63° (6x + 9° R-example-1
User StefanS
by
4.7k points