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Find a polynomial function of lowest degree

with rational coefficients that has the given
numbers as some of its zeros
2 + i, 2
A) f(x) = x3 + 7x2 + 12x + 10
B) f(x) = x3 - 6x2 + 13x - 10
C) f(x) = x3 + 6x2 + 13x + 10
D) f(x) = x3 - 2x2 - (3 - 4i) x + 6 + 8i

User Matt David
by
8.0k points

1 Answer

2 votes

Final answer:

Option B is the correct answer: f(x) = x^3 - 6x^2 + 13x - 10, as it is the polynomial function of the lowest degree with rational coefficients that includes the given zeros 2 + i and 2.

Step-by-step explanation:

To find a polynomial function of lowest degree with rational coefficients that has the numbers 2 + i and 2 as some of its zeros, we first need to recognize that any polynomial with rational coefficients and a complex zero must also have the complex conjugate of that zero as a root. Therefore, the roots of the polynomial must include 2 + i, 2 - i (the complex conjugate of 2 + i), and 2.

The polynomial can be found by taking the product of (x - (2 + i)), (x - (2 - i)), and (x - 2). Expanding this product gives us:

(x - 2 - i)(x - 2 + i)(x - 2) = ((x - 2)^2 - i^2)(x - 2) = ((x^2 - 4x + 4) + 1)(x - 2) = (x^2 - 4x + 5)(x - 2)

Expanding further, we get:

x^3 - 2x^2 - 4x^2 + 8x + 5x - 10 = x^3 - 6x^2 + 13x - 10

Therefore, the correct polynomial is option B: f(x) = x^3 - 6x^2 + 13x - 10.

User Vitalij
by
8.2k points