85.6k views
5 votes
What is the simplified expression for [(p^2)(q^5)]*[(p^-4)(q^5)]^-2?

1 Answer

3 votes

Final answer:

The simplified expression for [(p^2)(q^5)]*[(p^-4)(q^5)]^-2 is p^10.

Step-by-step explanation:

To simplify the expression [(p^2)(q^5)]*[(p^-4)(q^5)]^-2, we can first simplify the expressions inside the parentheses.
(p^2)(q^5) = p^2 * q^5
(p^-4)(q^5) = p^-4 * q^5

Next, take the negative exponent of the second expression and reciprocate both the base and the exponent.
p^-4 = 1/(p^4).

Now substitute the simplified expressions back into the original expression:
[(p^2)(q^5)]*[(p^-4)(q^5)]^-2 = p^2 * q^5 * [1/(p^4) * q^5]^-2

Apply the rule that states that when we raise a fraction to a negative exponent, we can flip the fraction and make the exponent positive:
[1/(p^4) * q^5]^-2 = [(p^4)/q^5]^2

Now multiply the terms together:
p^2 * q^5 * [(p^4)/q^5]^2 = p^2 * (p^4)^2 = p^2 * p^8 = p^(2+8) = p^10

Therefore, the simplified expression is p^10.

User Danylo Mysak
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories